equal unequal Counters

>>> import collections >>> collections.Counter("abc") == collections.Counter("cab") True >>> collections.Counter("abc").most_common() [('a', 1), ('b', 1), ('c', 1)] >>> collections.Counter("cab").most_common() [('c', 1), ('a', 1), ('b', 1)] As demonstrated above, collections.Counter.most_common orders elements with equal counts in order of first appearance: “Elements with equal counts are ordered in the order first encountered”. But == looks at set equality. Handy for checking for palindromes without doing a sort (and so hopefully O(n) vs O(n log n)): Counter(s) == Counter(t). Just slightly disconcerting to have two objects that will return True for == but yet still have non-identical results for another method.

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